On A Coordinate Plane What Is The Distance Between (4,-7) And (-5,-7)

On a coordinate plane what is the distance between (4,-7) and (-5,-7)

ANSWER : 9 u.c

STEP BY STEP EXPLANATION :

\mathsf{dAB=\sqrt{(X_{B}-X_{A})^{2}+(Y_{B}-Y_{A})^{2}}} \\\\\\ \mathsf{dAB=\sqrt{((-5)-4)^{2}+((-7)-(-7))^{2}}} \\\\\\ \mathsf{dAB=\sqrt{(-9)^{2}+(0)^{2}}} \\\\\\ \mathsf{dAB=\sqrt{81+0}} \\\\\\ \mathsf{dAB=\sqrt{81}} \\\\\\ \boxed{\mathsf{dAB=9~~u.c}}

Therefore, the distance is 9 u.c

Ok.


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